1(1,5) $42(No, that's incorrect. Try again.HINT: )$43($4255You have to take the square root of your answer to find c.)$44($4255You added the values of a and b. Use a2 + b2 = c2 .)$46($4255Use the Pythagorean formula, a2 + b2 = c2 . Solve for c. Check.)
If c is the longest side of the right trianglewith sides a, b, and c, find the length of themissing side when:a = 2 and b = 3.c = ? iT1 1 If c is the longest side of the right trianglewith sides a, b, and c, find the length of themissing side when:a = 2 and b = 3.+20 Use a2 + b2 = c2 . (2)2 + (3)2 = c2 p 8 5:4 = c2 p c is the length of one side of a triangle. c mustbe c2POSITIVEc0. c = 5 p = 4
4#5@$43#22@$44_$46
1(1,5) $42(No, that's incorrect. Try again.HINT: )$43($4255You have to take the square root of your answer to find b.)$44($4255You subtracted the values of c and a. Use b2 = c2 - a2 .)$46($4255Use the Pythagorean formula, a2 + b2 = c2 . Solve for b. Check.)
2(1e3*)3(1e4*)4(1e5*)5(3e3*)6(2e10/z)22(4e2-)
If c is the longest side of the right trianglewith sides a, b, and c, find the length of themissing side when: a = 2 and c = 4.b = ? iT1 1 If c is the longest side of the right trianglewith sides a, b, and c, find the length of themissing side when: a = 2 and c = 4.+20 Use a2 + b2 = c2 . (2)2 + b2 = (4)2 p +6 b2 = (4)2 - (2)2 p +6 b2 = 5 p b is the length of one side of a triangle. b mustbe c2POSITIVEc0. b = 5 p = 3
3#5@$43#22@$44_$46
1(1,5) $42(No, that's incorrect. Try again.HINT: )$43($4255You have to take the square root of your answer to find a.)$44($4255You subtracted the values of c and b. Use a2 = c2 - b2 .)$46($4255Use the Pythagorean formula, a2 + b2 = c2 . Solve for a. Check.)
2(1e3*)3(1e4*)4(1e5*)5(2e2*)6(3e10/z)22(4e3-)
If c is the longest side of the right trianglewith sides a, b, and c, find the length of themissing side when: b = 3 and c = 4.a = ? iT1 1 If c is the longest side of the right trianglewith sides a, b, and c, find the length of themissing side when: b = 3 and c = 4.+20 Use a2 + b2 = c2 . a2 + (3)2 = (4)2 p +6 a2 = (4)2 - (3)2 p +6 a2 = 5 p a is the length of one side of a triangle. a mustbe c2POSITIVEc0. a = 5 p = 2
2#5@$43#22@$44_$46
1(14,18) $42(No, that's incorrect. Try again.HINT: )$43($4255First find the distance traveled by each car using d = rt.)$44($4255You added the distance each car traveled. Use the Pythagorean formula to find the distance apart.)$45($4255You have to take the square root of your answer to find the distance the two cars are apart.)$46($4255First solve for the distance using d = rt. Then use the Pythagorean formula. Check your work.)
Two cars leave San Antonio, Texas, at the same time. One travels north at 2 mph and the other travels east at3 mph. How far apart are they after 2 hours?The cars will be ? miles apart. iT1 1 Two cars leave San Antonio, Texas, at the same time. One travels north at 2 mph and the other travels east at3 mph. How far apart are they after 2 hours? +5+10 "G\RTR12D.20.10+10+15 ca = (2 hours)(2 mph) +16,+0 San Antonio b = (2 hours)(3 mph) a2 + b2 = c2 p 6:32 + 72 = c2 p 5 = c p The cars are 5 miles apart.
5#5/2@$43#6+7@$44#20@$45_$46
1(3,10)11(1,10) $42(No, that's incorrect. Try again.HINT: )$43($4255You have to take the square root of your answer to find the length of the rectangle.)$44($4255You added the lengths of the sides. The diagonal is the hypotenuse. Use the Pythagorean formula.)$46($4255The diagonal is the hypotenuse of a right triangle. Use the Pythagorean formula. Check your work.) n(1=4)n(1=6)n(1=9)n(11>1&1>3)
Two sides of a rectangle measure 1 metersand 2 meters. How long is the diagonal ofthe rectangle? ? meters iT1 1a Two sides of a rectangle measure 1 metersand 2 meters. How long is the diagonal ofthe rectangle? D DR(160,40,360,120) MT(160,40) L(200,80) j29,12 c j1,12 a = 1 meters j21,21 b = 2 meters j0,22 a2 + b2 = c2 p 1:22 + 2:22 = c2 p 3 = c The diagonal is 3 meters long.
3#20@$43#23@$44_$46
1(3,10)11(1,10) $42(No, that's incorrect. Try again.HINT: )$43($4255You have to take the square root of your answer to find the height of the flagpole.)$44($4255You subtracted the distances. The long distance forms the hypotenuse and the other forms the base.)$46($4255The long distance forms the hypotenuse and other forms the base. Use the Pythagorean formula. Check.) n(1=4)n(1=6)n(1=9)n(11>1&1>3)
The distance from the top of a flagpole to apoint 1 feet from the base of the flagpoleis 3 feet. How high is the flagpole? ? feet iT1 1a The distance from the top of a flagpole to apoint 1 feet from the base of the flagpoleis 3 feet. How high is the flagpole? D MT(100,33) L(90,90) L(0,90) M(0,90) L(90,0) M(10,-8) L(0,8) L(-10,0) j14,12 c = 3 feet j6,12 a j9,21 b = 1 feet j0,23 a2 + b2 = c2 p a2 + 1:22 = 32 p a2 + 4:3 = 5 p ct23,0,32,60 a2 = 6 a = 2 The flagpole is 2 feet high.
2#6@$43#22@$44_$46
1(75,99)2(50,75) $42(No, that's incorrect. Try again.HINT: )$43($4255You have to take the square root of your answer and round to find the distance from the starting point.)$44($4255You added the distances. Distance across forms one leg and the distance downstream forms the other leg.)$46($4255The river's width and the distance carried form the legs of a right triangle. Solve and Check.) n(1=2)
A swimmer crosses a river which is 1 feet wide.The current carries her downstream 2 feet. Abouthow far away is she from her starting point? Give the answer as a number rounded to the nearesttenth. About ? ft iT1 1a A swimmer crosses a river which is 1 feet wide.The current carries her downstream 2 feet. Abouthow far away is she from her starting point? DMT(40,41) LT(42,43) LT(44,45) MT(42,43) LT(44,45) MT(95,68) L(-10,0)L(0,-8) +10,+0 1 ft2 ft+10 ?The Pythagorean formula lets us find the hypotenuse of a right triangle when thetwo legs are known. p cs The two legs of the right triangle are the river'swidth, 1, and the distance downstream, 2. p Substitute those values into the formula.hypotenuse = (leg)2 + (leg)2 p 10 = 12 + 22 p 11= 4 p The swimmer is about 3 feet from her starting point.
3 3"ft"#4@$43#20@$44_$46
1(9,16)2(6,12) $42(No, that's incorrect. Try again.HINT: )$43($4255You have to take the square root of your answer to find the width of the base.)$44($4255You subtracted the lengths. The roof forms the hypotenuse and the wall forms the leg.)$46($4255The roof forms the hypotenuse and the wall forms the leg. Use the Pythagorean formula to find the base.) n(2>=1)
A triangular-shaped lean-to has a sloping roof which is 1 feet long. The back wall of the lean-to is 2 feet high. About how many feet wide is the base of the structure? Give the answer as a number rounded to thenearest tenth. About ? ft iT1 1a A triangular-shaped lean-to has a sloping roof which is 1 feet long. The back wall of the lean-to is 2 feet high. About how many feet wide is the base of the structure? DMT(40,41) LT(42,43) LT(44,45) MT(42,43) LT(44,45) MT(245,102) L(10,0) L(0,8) +10,+0 1 ft+28,+02 ft+16,+0 ? The Pythagorean formula lets us find one legof a right triangle when the hypotenuse and other leg are known. p cs The hypotenuse is the length of the sloping roof,1 feet, and one of the legs is the height of theback wall, 2 feet. p Substitute those values into the formula.leg = (hypotenuse)2 - (leg)2 p = 12 - 22 p = 4 p The base of the lean-to is about 3 feet wide.
